when(candidateService.findById(1)).thenReturn(new Candidate());

我想扩展这种行为为任何整数(不一定为1)

如果我吃惊

when(candidateService.findById( any(Integer.class)  )).thenReturn(new Candidate());

我有编译错误

The method findById(Integer) in the type CandidateService is not
applicable for the arguments (Matcher)

UPDATE

进口：

import static org.junit.Assert.assertEquals;
import static org.mockito.Matchers.anyInt;
import static org.mockito.Matchers.anyString;
import static org.mockito.Mockito.mock;
import static org.mockito.Mockito.times;
import static org.mockito.Mockito.verify;
import static org.mockito.Mockito.when;
import static org.springframework.test.web.servlet.result.MockMvcResultMatchers.status;

import java.util.ArrayList;
import java.util.HashSet;

import org.junit.Before;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.mockito.InjectMocks;
import org.mockito.Mock;
import org.mockito.MockitoAnnotations;

解决方法

尝试anyInt()：

when(candidateService.findById( anyInt())).thenReturn(new Candidate());

例如我的项目中有anyLong()：

when(dao.getAddress(anyLong())).thenReturn(Arrays.asList(dto));

编辑：
您必须导入：

import static org.mockito.Matchers.anyInt;